4n^2+6n-48=-8

Solution for 4n^2+6n-48=-8 equation:

4n^2+6n-48=-8

We move all terms to the left:

4n^2+6n-48-(-8)=0

We add all the numbers together, and all the variables

4n^2+6n-40=0

a = 4; b = 6; c = -40;
Δ = b2-4ac
Δ = 62-4·4·(-40)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-26}{2*4}=\frac{-32}{8}
=-4
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+26}{2*4}=\frac{20}{8}
=2+1/2
$